(y+2)^2=2y^2+5y-8

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Solution for (y+2)^2=2y^2+5y-8 equation: 



(y+2)^2=2y^2+5y-8

We move all terms to the left:

(y+2)^2-(2y^2+5y-8)=0

We get rid of parentheses

-2y^2+(y+2)^2-5y+8=0

We add all the numbers together, and all the variables

-2y^2-5y+(y+2)^2+8=0

We move all terms containing y to the left, all other terms to the right

-2y^2-5y+(y+2)^2=-8

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